def count(a):
    r = []
    last = 0
    c = 0
    for i, v in enumerate(a):
        if v:
            if not c:
                last = i
            c += 1
        elif c:
            r.append((last, c))
            c = 0
    else:
        if c:
            r.append((last, c))
    return r

print(count([1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1]))
# [(0, 4), (10, 1), (12, 1), (16, 6)]