# Takes two inputs. 
# Two small floats.
# Example, price = 0.03403234, vol= 0.0025

# for given price and volume. calulate the next valid price for same volume by incrementing price
# smallet increment is in price can only be 0.00000001

def calc(price, vol):
    inc    = 0.000000010
    exp    = 8
    p      = price
    v      = vol
    i      = 0
    while True:
        i+=1
        p += inc
        # If the sum have any fractions|desimals larger than 0 then its not valid.
        
        sum = format(float(v) * (float(p) * 10 ** exp),'.8f')
        x = int(sum.split(".")[1])
        if x == 0:
            return [int(float(sum)), p]
        
        # Takes to long i guess, just return zero
        if i > 10000:
            return [0,0]

            
vol = 0.0025
old_price = 0.03403234
res = calc(old_price, vol)

print("vol      :", format(vol, '.8f'))
print("old price:", format(old_price, '.8f'))
print("new price:", format(r[1], '.8f'))